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Mathematics in Trades and Life

Section 3.3 Identifying Rates

This section addresses the following topics.
  • Interpret data in various formats and analyze mathematical models
This section covers the following mathematical concepts.
  • Identify rates as linear, quadratic, exponential, or other (critical thinking)
So far we have looked at linear models. We will add quadratic, exponential, and some variations in later sections. One of the ways we distinguish between models is by the rate at which they grow. Often the rate at which something is happening is more important than how much there currently is. This section presents two methods for identifying rates from tables of data. How to identify each type by graph is presented in the appropriate chapter and section.

Subsection 3.3.1 Differences

One way to measure rates is to look at the differences between data points. Calculating these differences is illustrated in the table below.
Table 3.3.1. Tienโ€™s Salary
Year Salary Difference
2017 $52,429.33
2018 $55,050.80 $55,050.80-$52,429.33=$2,621.47
2019 $57,803.34 $57,803.34-$55,050.80=$2,752.54
2020 $60,693.50 $60,693.50-$57,803.34=$2,890.17
2021 $63,728.18 $63,728.18-$60,693.50=$3,034.68
2022 $66,914.59 $66,914.59-$63,728.18=$3,186.41
2023 $70,260.32 $70,260.32-$66,914.59=$3,345.73
2024 $73,773.33 $73,773.33-$70,260.32=$3,513.02
In order to see how these differences can help us distinguish between linear and other models, consider Vasyaโ€™s salary in Exampleย 3.2.20. We know that the difference between each yearโ€™s salary is $5000.00, because we are told that was the raise each year. This is linear model. In contrast Tienโ€™s raises are different each year (they grow year to year). This means his salary does not grow linearly.

Example 3.3.2. Differences for Atmospheric Pressure Model.

Consider the model in Exampleย 3.2.35. Tableย 3.3.3 calculates the differences every 2000 ft. Notice that the differences are all the same namely -2.00. This model is linear.
Tableย 3.3.4 calculates the differences every 1000 ft. In this table the differences are all -1.00. This still indicates that the model is linear. It does not matter what interval we choose. If the differences over evenly spaced intervals are the same, then the model is linear.
The rates we obtained in both tables do match. Consider \(\frac{-2.00}{2000} = \frac{-1.00}{1000}\text{.}\)
Table 3.3.3. Atmospheric Pressure Differences (2000 ft intervals)
Altitude (ft MSL) Expected Pressure (inHg) Difference
0 29.92
2000 27.92 27.92-29.92=-2.00
4000 25.92 25.92-27.92=-2.00
6000 23.92 23.92-25.92=-2.00
8000 21.92 21.92-23.92=-2.00
Table 3.3.4. Atmospheric Pressure Differences (1000 ft intervals)
Altitude (ft MSL) Expected Pressure (inHg) Difference
0 29.92
1000 28.92 28.92-29.92=-1.00
2000 27.92 27.92-28.92=-1.00
3000 26.92 26.92-27.92=-1.00
4000 25.92 25.92-26.92=-1.00

Definition 3.3.5. Linear Relation.

A relation is linear if and only if the rate of change is constant.
This states that a linear model grows by the same amount from one step to the next (rate of change or difference). This equal growth results from the ratio \(m\) in the form \(y=mx+b\text{.}\) Consider the specific case \(y=3x+2\text{.}\) In the table below notice that the differences are all the same and that the difference is 3. 3 is the ratio from the equation. This is always the case. The slope is how fast the line grows.
Table 3.3.6. Differences for Lines
\(x\) \(y\) Difference
\(0\) \(2\)
\(1\) \(5\) 5-2=3
\(2\) \(8\) 8-5=3
\(3\) \(11\) 11-8=3
\(4\) \(14\) 14-11=3
Notice we used this constant addition property when working with ratio problems like Exampleย 2.3.4. Relations defined by fixed ratios like these are linear.
For linear data consecutive differences are always the same. The next examples (Exampleย 3.3.7 to Exampleย 3.3.10) illustrate known, non-linear data and how the differences for those look.

Example 3.3.7. Quadratic Data.

Consider Tableย 3.3.8. The first differences (what we calculated above) are not the same. Thus this data is not linear.
However, the first differences increase in a suspiciously simple pattern (odd numbers). Checking the second differences (the differences of the 1st differences) we see a linear pattern. This turns out to be the pattern for all quadratic data.
Table 3.3.8. Quadratic Data
\(n\) \(n^2\) 1st difference 2nd difference
1 1
2 4 4-1=3
3 9 9-4=5 5-3=2
4 16 16-9=7 7-5=2
5 25 25-16=9 9-7=2
6 36 36-25=11 11-9=2

Definition 3.3.9. Quadratic Relation.

A relation is quadratic if and only if the second differences are constant.

Example 3.3.10. Exponential Data.

Consider Tableย 3.3.11. The differences are not the same nor do they show the same pattern as quadratics. However, there is a pattern in the differences. Notice that the differences are exactly equal to the original data. This means that the rate of increase is determined by the current scale. In other words, the bigger it is, the faster it grows. This is the pattern of data that varies exponentially.
Table 3.3.11. Exponential Data
\(n\) \(2^n\) Difference
1 2
2 4 4-2=2
3 8 8-4=4
4 16 16-8=8
5 32 32-16=16
6 64 64-32=32
The next example illustrates that the differences for exponential data are not always exactly equal to the data.

Example 3.3.12. Exponential Data Differences.

Consider Tableย 3.3.13. The differences are not exactly equal to the original numbers. However, notice that \(6=2 \cdot 3\text{,}\) \(18=2 \cdot 9\text{,}\) and \(54=2 \cdot 27\text{.}\) The differences are double the original numbers. In general for exponential data the differences will be the original data scaled by some number.
Happily there is an easier way to determine that data is exponential shown in the next section.
Table 3.3.13. Exponential Data with Scale
\(n\) \(3^n\) Difference
1 3
2 9 9-3=6
3 27 27-9=18
4 81 81-27=54
5 243 243-81=162
6 729 729-243=486

Definition 3.3.14. Exponential Relation.

A relation is exponential if and only if the differences are a multiple of the original values, that is the rate is proportional to the value.

Subsection 3.3.2 Quotients

The previous section analyzed change as the difference (subtraction) of consecutive numbers (salaries in these examples). This section analyzes change using the percent increase for each pair of consecutive numbers.

Example 3.3.15. Salary Percent Incease.

We will first calculate the percent increase of salary each year for Tien and Vasya. Because salary numbers are exact, we will not use significant digits. Rather we will round to the nearest percent. This is in Tableย 3.3.16 and Tableย 3.3.17.
Notice that for Tien the percent increase is the same each year. It is 5%. For Vasya, the percent increase is not the same each year. How does the percent increase change for her?
Table 3.3.16. Percent Increase for Tien
Year Ratio Increase
2018 $55,050.80/$52,429.33 =1.05 5%
2019 $57,803.34/$55,050.80 =1.05 5%
2020 $60,693.50/$57,803.34 =1.05 5%
2021 $63,728.18/$60,693.50 =1.05 5%
Table 3.3.17. Percent Increase for Vasya
Year Ratio Increase
2018 $67,347.23/$62,347.23 =1.08 8%
2019 $72,347.23/$67,347.23 =1.07 7%
2020 $77,347.23/$72,347.23 =1.07 7%
2021 $82,347.23/$77,347.23 =1.06 6%

Definition 3.3.18. Exponential.

A relation is exponential if and only if the percent increase is constant.

Example 3.3.19.

The table below gives an amount of caffeine in the blood stream. This data is exponential with a ratio of 0.87. The ratio in this example means there is a 13% decrease per hour of caffeine in the blood stream. This is in contrast to the previous example which was an increasing exponential.
Hour Caffeine Ratio
0 95 mg
1 83 mg \(83/95 \approx 0.87\)
2 72 mg \(72/83 \approx 0.87\)
3 63 mg \(63/72 \approx 0.87\)
4 55 mg \(55/63 \approx 0.87\)
5 48 mg \(48/55 \approx 0.87\)
6 41 mg \(41/48 \approx 0.87\)
7 36 mg \(36/41 \approx 0.87\)
8 31 mg \(31/41 \approx 0.87\)
Although Definitionย 3.3.14 and Definitionย 3.3.18 are phrased differently they both accurately describe exponential relations. Generally it is easier to test if data is exponential by testing the ratios of terms rather than the differences. Tableย 3.3.20 shows an example of analyzing data using both differences and ratios. Notice that the differences are a scaled version of the original data (scaled by \(1/3\)). The ratio from the quotient is \(4/3\) which gives about a 33% increase. For the curious the data was generate by \(5\left(\frac{4}{3}\right)^n\text{.}\)
Table 3.3.20. Exponential Data 2 Ways
Data Difference Ratio
\(\frac{20}{3}\)
\(\frac{80}{9}\) \(\frac{20}{9}=\frac{1}{3} \cdot \frac{20}{3}\) \(\frac{4}{3} \approx 1.33\)
\(\frac{320}{27}\) \(\frac{80}{27}=\frac{1}{3} \cdot \frac{80}{9}\) \(\frac{4}{3} \approx 1.33\)
\(\frac{1280}{81}\) \(\frac{320}{81}=\frac{1}{3} \cdot \frac{320}{27}\) \(\frac{4}{3} \approx 1.33\)
\(\frac{5120}{243}\) \(\frac{1280}{243}=\frac{1}{3} \cdot \frac{1280}{81}\) \(\frac{4}{3} \approx 1.33\)
\(\frac{20480}{729}\) \(\frac{5120}{729}=\frac{1}{3} \cdot \frac{5120}{243}\) \(\frac{4}{3} \approx 1.33\)

Subsection 3.3.3 Extrapolation

In Exampleย 3.2.6 we found a value between two entries in a table. That is interpolation. In other cases we want to find a value past the end of a table. This is called extrapolation.

Example 3.3.22. Extrapolation from a Table.

Based on Tableย 3.3.1 what do we expect Tienโ€™s salary to be in 2022, 2025?
From Exampleย 3.3.15 we know each entry is 1.05 times the previous yearโ€™s salary. Because that was the pattern every year, we might safely suppose it will occur again. Thus we expect his 2022 salary to be \(1.05 \cdot \$73,773.33 \approx \$77,462.00\text{.}\)
To extrapolate to 2025 we repeat this process for 2023, 2024, and 2025.
\begin{align*} 1.05 \cdot \$77,462.00 & \approx \$81,335.10.\\ 1.05 \cdot \$81,335.10 & \approx \$85,401.85.\\ 1.05 \cdot \$85,401.85 & \approx \$89,671.94. \end{align*}
If his raises continue at the same rate he will have a salary of $89,671.94 in 2025.

Example 3.3.23.

Based on Tableย 3.2.21 what do we expect Vasyaโ€™s salary to be in 2025, 2028?
From Exampleย 3.2.20 we know that Vasya has received a $5,000 raise each year. Because that has been the pattern, we might safely suppose it will continue. Thus we expect her 2025 salary to be
\begin{equation*} \$97,347.23+\$5,000.00 = \$102,347.23. \end{equation*}
To calculate her expected 2028 salary we note that is 4 years after 2024, so she should have four raises of $5,000 each. Her expected salary will be
\begin{equation*} \$97,347.23+4(\$5,000.00) = \$117,347.23. \end{equation*}
Notice that in both of these examples we needed to know the growth rate (i.e., exponential or linear respectively) before we could extrapolate.

Exercises 3.3.4 Exercises

Identifying Rates.

Determine from the tables of data what the rate of growth is.

Extrapolating.

Identify the type of relation and extrapolate to write a few more elements.