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Mathematics in Trades and Life

Section 2.3 Ratios

This section addresses the following topics.
  • Interpret data in various formats and analyze mathematical models
  • Read and use mathematical models in a technical document
This section covers the following mathematical concepts.
  • Set up and solve proportions (skill)
A ratio expresses a fixed relationship between two quantities. This section illustrates using ratios to calculate amounts subject to a ratio and presents how to recognize what a ratio does and cannot tell us. Note, percents are simply ratios scaled to parts per 100, that is, what we know about percents is applicable here.

Subsection 2.3.1 Example Ratios

Example 2.3.1.

Simple syrup consists of one cup of sugar and one cup of water which is heated until the sugar is disolved. There are multiple ratios that express this combination. \(\frac{1 \text{ cup sugar}}{1 \text{ cup water}}\text{,}\) \(\frac{7.05 \text{ oz}}{8 \text{ oz}}\) ratio of sugar to water by weight, \(\frac{7.05 \text{ oz}}{15.05 \text{ oz}}\) ratio of sugar to simple syrup.
Each of these ratios indicates that there is a fixed amount of sugar relative to the water or resulting syrup. That is, is if we made simple syrup with 2 cups of sugar we would need 2 cups of water because
\begin{equation*} \frac{2 \text{ cups sugar}}{2 \text{ cups water}} = \frac{1 \text{ cup sugar}}{1 \text{ cup water}} \end{equation*}
by reducing fractions.

Example 2.3.2.

In a neighborhood there are 7 dogs and 12 cats. To express the relative number dogs and cats we can write the ratio
\begin{equation*} \frac{7 \text{ dogs}}{12 \text{ cats}} \end{equation*}
Note that \(\frac{7}{12} \approx 0.58 \lt 1\text{.}\) Because it is less than one the ratio tells us that there are fewer dogs than cats in this neighborhood.
We could also write \(\frac{12 \text{ cats}}{7 \text{ dogs}}\) to express the exact same relationship. Note that \(\frac{12}{7} \approx 1.7 \gt 1\text{.}\) Because it is greater than one the ratio tells us that there are more cats than dogs in the neighborhood (same result as above).

Example 2.3.3.

Rates are expressed as ratios. The following rates are all written as ratios.
\begin{equation*} \frac{35 \text{ miles}}{1 \text{ hour}} \end{equation*}
\begin{equation*} \frac{8 \text{ gallons}}{1 \text{ minute}} \end{equation*}
Notice that these (and most rates) are expressed with the denominator being one. This makes it easier to calculate as will be seen below. Frequently we will skip writing the one in the denominator, e.g., \(\frac{35 \text{ miles}}{\text{hour}}\text{.}\)
Rates are not required to have a denominator of one and sometimes a different denominator is easier for calculation. For example
\begin{equation*} \frac{3 \text{ nm}}{2 \text{min}}=\frac{1.5 \text{ nm}}{1 \text{ min}} \end{equation*}

Subsection 2.3.2 Using Ratios

Just like percents (which are ratios written in decimal form) if we know a ratio and one of the amounts we can calculate the other amount. The method is the same as with percents, namely multiplying the correct number or solving an equation.

Example 2.3.4. Ratio: Airspeed.

According to the airplane flight manual the Diamond DA-20 cruises at the rate (speed) of
\begin{equation*} \frac{110 \text{ nautical miles}}{1 \text{ hour}}\text{.} \end{equation*}
Cruise is a portion of flight in which the speed is typically constant. How far can the plane cruise in 2.5 hours?
We notice that the speed units (nautical miles per hour) match with the hours. If the speed and time are multiplied we will end up with a distance. Thus the units suggest we can multiply.
\begin{align*} \text{Distance} & = \frac{110 \text{ nm}}{1 \text{ hr}} \cdot 2.5 \text{ hr}\\ & = \frac{110 \text{ nm}}{1 \cancelhighlight{\text{ hr}}} \cdot \frac{2.5 \cancelhighlight{\text{ hr}}}{1}\\ & = 110 \cdot 2.5 \text{ nm}\\ & = 275 \text{ nm}\text{.} \end{align*}
There is another approach to the same question.

Example 2.3.5. Ratio: Airspeed by Table.

According to the airplane flight manual the Diamond DA-20 cruises at the rate (speed) of
\begin{equation*} \frac{110 \text{ nautical miles}}{1 \text{ hour}}\text{.} \end{equation*}
How far can the plane cruise in 2.5 hours?
Because this ratio remains the same during cruise we can break the problem down into pieces. Based on the ratio (speed) in the first hour the plane will fly 110 nm. In the second hour it will fly another 110 nm. In the last half hour it will fly half of the distance which is \(110/2=55\) nm. Thus in 2.5 hours it will fly \(110+110+55=275\) nm.
Some manuals provide tables to make this method convenient. See TableΒ 2.3.6 for a table of this sort. How far can the DA-20 cruise in 2.7 hours? We need to write 2.7 as the sum of numbers in the table. One way is \(2.7 = 2+0.5+0.2\text{.}\) From the table we know it will fly 220 nm in 2 hours, 55 nm in an additional 0.5 hours, and 22 nm in the final 0.2 hours. Thus it will fly \(220+55+22=297\) nm.
While this method makes sense, it is less efficient than simply multiplying as in the previous example.
Table 2.3.6. Airspeed and Distance
Time Distance
0.1 hour 11 nm
0.2 hour 22 nm
0.3 hour 33 nm
0.4 hour 44 nm
0.5 hour 55 nm
1 hour 110 nm
2 hour 220 nm
3 hour 330 nm

Example 2.3.7.

Water is flowing out of a hose at a rate of 11 gallons per minute. How many gallons have come out after 2.7 minutes?
Solution.
We can set this up like the calculation in ExampleΒ 2.3.4. In that example multiplied the ratio (nm/hr) by the number of hours which gave us nm. Here we multiply the ratio (gal/min) by the number of minutes which will give us gallons.
\begin{align*} \text{Volume} & = \frac{11 \text{ gal}}{1 \text{ min}} \cdot 2.7 \text{ min}\\ \text{Volume} & = \frac{11 \text{ gal}}{1 \cancelhighlight{\text{ min}}} \cdot \frac{2.7 \cancelhighlight{\text{ min}}}{1}\\ & = 11 \cdot 2.7 \text{ gal}\\ & = 29.7 \text{ gal}\text{.} \end{align*}

Example 2.3.8.

Based on data from the FDA the average amount of mercury found in fresh or frozen salmon is 0.022 ppm (parts per million). This means there are 0.022 mg of mercury in one liter of salmon. If a meal portion of salmon is 0.0020 liters how much mercury is consumed?
Solution.
We can use the ratio \(\frac{0.022 \; \text{mg}}{1 \; \ell}\text{.}\) We apply this ratio to the given volume of 0.0020 liters.
\begin{equation*} \frac{0.022 \text{ mg}}{1 \; \ell} \cdot 0.0020 \; \ell = 0.000044 \text{ mg} \end{equation*}
The method for ratios that have a number other than one in the denominator is the same.

Example 2.3.10.

A saline solution intended for nasal rinsing has a ratio of 2.5 g of salt (sodium chloride) per 240 mL of pure water. How much salt is needed to make a half liter of this saline solution? Your scale is precise to a gram. Round appropriately.
We can apply the given ratio (2.5 g/240 mL) to the given amount (0.5 L). First it will be convenient to convert a half liter to milliliters. This is also a ratio problem. See TableΒ 1.1.8 for the conversion ratio.
\begin{equation*} \frac{1000 \text{ mL}}{1 \text{ L}} \cdot 0.5 \text{ L} = 500 \text{ mL}. \end{equation*}
The units suggest that we can multiply the saline solution ratio by the desired volume.
\begin{equation*} \frac{2.5 \text{ g}}{240 \text{mL}} \cdot 500 \text{ mL} \approx 5.208333335 \approx 5 \text{ g}\text{.} \end{equation*}
We round to units, because we cannot measure more precisely.

Example 2.3.11.

At 90 nm/hr a plane travels 3 nm/2 min. How far will it travel in 6 minutes?
Solution.
We can multiply the given ratio (nm/hr) by the given amount (min) to calculate distance (nm).
\begin{equation*} \frac{3 \text{ nm}}{2 \text{ min}} \cdot 6 \text{ min} = 9 \text{ nm}. \end{equation*}

Subsection 2.3.3 Understanding Ratios

Like percents ratios tell us a relationship between two quantities but do not tell us how much. For example if a cookie recipe calls for 2 cups of milk for every 3 eggs, we do not know how many eggs are needed for a dozen cookies. We would also need to know either how many cups of milk per dozen or how many eggs per dozen.
Ratios may be based on rounded numbers. For example the unit convesion \(\frac{8 \text{ kilometers}}{5 \text{ miles}}\) is convenient for quick calculations. However, \(8/5 = 1.6 \approx 1.609344\) which is a more accurate conversion rate. If we are trying to convert β€œTempo 30” (a speed limit of 30 kph) to mph this ratio is fine. If we are sending a satellite to another planet, we will need a more accurate conversion.
Rounding may occur to make the ratio easier to comprehend. For example according to an article by the U.S. Census Bureau 1 in 6 people in the U.S. was aged 65 and over. Because this ratio uses small numbers it is easy to understand. It is much easier to read and use than a more precise estimate of \(\frac{57822315}{333287562}\text{.}\)

Exercises 2.3.4 Exercises

Writing Ratios.

Write the ratios requested.

Ratios in Contexts.

Read the description, and write the requested ratio.

Using Ratios in Contexts.

Answer the question using ratios.

Interpretting Ratios.

Determine what each ratio tells us about the circumstances.